consider a crash test between two identical cars. The cars are pulled to the des

Question

consider a crash test between two identical cars. The cars are pulled to the desired speed and then crashed. There is no acceleration due to the engine or breakes during the collision. The two arrows to the right show the velocities of the cars just before the collisions. V1i -----> <-- V2i

below are several possible velocities for the two cars after the collision. Which of these are physically possible outcomes for the collision? There may be more than one correct answer, you must identify them all correctly for full credit. (the arrows are drawn to scale)

a) <-----V1f V2f-------------->

b) V1f -> V2f ->

c) <--V1f V2f=0

d) V1F=0 and V2f=0

e) <-----V1f V2f-->

f) <--V1f V2f----->

Explanation / Answer

The momentum b4 collision is M(V1i+V2i) By conservation of linear momentum as there r no external forces on the system, the momentum after collision shud remain same. M(V1i+V2i)=M(V1f+V2f) So vector V1f+V2f shud be same as (V1i+V2i) in length Only b) and f) match the criteriA.

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