On a certain game show, contestants spin a wheel when it is their turn. One cont

Question

On a certain game show, contestants spin a wheel when it is their turn. One contestant gives the wheel an initial angular speed of 3.20 rad/s. It then rotates through one-and-one-quarter revolutions and comes to rest on the BANKRUPT space. Through what angle has the wheel turned when its angular speed is 1.90 rad/s?

1.25rev(2?rad/1rev)= 7.854rad

? = ?2/2?

-(3.2)2/(2(?))= ___rad

I don't know whats wrong with my angular acceleration. When its .69, my answer is 4.63 which "Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.is according to web assign.

Explanation / Answer

As we know

v2 = u2 + 2aS

which is analogus to

f2 = o2 + 2**

For this particular case

  o = 3.20 rad/s

  f = 0.00 rad/s

= 1.25*2* = 7.8540 rad

= (f2 - o2)/2 = - 0.652 rad/s2

Now abgle travelled when f = 1.90 rad/s

= (f2 - o2)/2 = 5.084 rad or 291.31o

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