Vibration from a 475 Hz tuning fork sets up standing waves on a string clamped a
ID: 2173077 • Letter: V
Question
Vibration from a 475 Hz tuning fork sets up standing waves on a string clamped at both ends (one of which you may take as x=0). The travelling wave speed on this string is 380 m/s. The standing wave has four anti-nodes and an amplitude of 4.0 mm.(a) What is the length of the string?
____m
(b) Write an equation for the transverse displacement of the string as a function of position and time:
y(x,t) = (____mm) sin (____m^-1 x ) cos (____s^-1 t)
(c) What is the wavelength of the traveling waves that form this standing wave?
____m
Explanation / Answer
C.wavelength=wavespeed/frequency=380/475m=.8 METRES.
A.AS THERE ARE 4 ANTINODES
L=2*WAVELENGTH=380/475*2=1.6METRES
B.Y=4MMSIN(2/.8)COS(2*475)
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