A jet takes off from SFO to YUL. The distance between the airports is 4100 km. A

Question

A jet takes off from SFO to YUL. The distance between the airports is 4100 km. After a 1 hour layover, the jet returns to SFO. The total time for the round trip (including the layover) is 11hr 52 mins. If the westbound trip (from YUL to SFO) takes 48 more minutes than the eastbound portion, calculate the time for each leg of the trip. What is the average speed of the overall trip? What is the average speed without the layover?

Explanation / Answer

westbound trip = 48+eastbound portion eastbound portion+westbound trip+Layover = (11*60)+52 = 660+52 = 712 =>48+2eastbound portion+60 = 712 =>2eastbound portion = 604 =>eastbound portion = 302 Minutes = 5hours 2mins westbound portion = 5 hours 50mins Average speed = (8200000)/(712*60) = 191.95m/sec Average speed without layover = (8200000)/(652*60) = 209.61m/sec

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