A mass hangs on the end of a massless rope. The pendulum is held horizontal and

Question

A mass hangs on the end of a massless rope. The pendulum is held horizontal and released from rest. When the mass reaches the bottom of its path it is moving at a speed v = 2.7 m/s and the tension in the rope is T = 20.2 N.
1) How long is the rope?

2) What is the mass?

3) If the maximum mass that can be used before the rope breaks is mmax = 1.59 kg, what is the maximum tension the rope can withstand? (Assuming that the mass is still released from the horizontal.)

4)
Now a peg is placed 4/5 of the way down the pendulum

Explanation / Answer

use the follwing formulaes 1) v^2= 2gL 2) LT/(v^2 + Lg) =m 3) T = mv^2/L + mg 4) v^2 = 2gh...... h=(4/5)L

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