1. Barack and Melania plan on having a child. Barack has long eyelashes while Me
ID: 217128 • Letter: 1
Question
1. Barack and Melania plan on having a child. Barack has long eyelashes while Melania has short eyelashes. A dominant allele gives rise to the long eyelash trait. With respect to this trait, Barack is heterozygous and Melania is homozygous. a. What is Barack's genotype? b. What is the probability (or likelihood) that their child will have short eyelashes? c. What is the probability that their child will have long eyelashes? d. What is the probability that their child will be homozygous for long eyelashes?Explanation / Answer
Let the dominant allele be denoted by E. And the recessive one as e.
A). Here Barack is heterozygous for long eyelashes so his genotype will be Ee.
B). Melania is homozygous for short eyelashes so her genotype will be ee.
On crossing both genotypes: Ee X ee, we get 2 heterozygous child Ee and 2 homozygous for ee.
So the probability of getting a child with short eyelashes will be 50% or .5
C). As stated above, 2 offsprings produced are heterozygous having Ee. They will have long eye lashes. So the probabilty here also is 50% or .5
D). As stated above, there is no chance of producing offspring with EE genotype. So the probabilty of getting a homozygous child for long eye lashes will be 0.
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