Two horizontal forces, and are acting on a box, but only is shown in the drawing

Question

Two horizontal forces, and are acting on a box, but only is shown in the drawing. can point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface. Suppose that and the mass of the box is 4. 4 kg. Find the magnitude and direction of when the acceleration of the box is +5. 6 m/s2, -5. 6 m/s2, and 0 m /s2.

Explanation / Answer

by newton second law, mass*acceleration = total force a)a = 5.6 m/s^2,F1 = 3.8 N , m = 4.4 kg ma = F1+F2 => 4.4*5.6 = 3.8+F2 => F2 = 20.84 N => F2 = 20.84 N in positive x Ans b)a = -5.6 m/s^2,F1 = 3.8 N , m = 4.4 kg ma = F1+F2 => 4.4*-5.6 = 3.8+F2 => F2 = -28.44 N => F2 = 28.44 N in negative x Ans c)a = 0 m/s^2,F1 = 3.8 N , m = 4.4 kg ma = F1+F2 => 4.4*0 = 3.8+F2 => F2 = -3.8 N => F2 = 3.8 N in negative x Ans

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