(Problem 47b, part 2) Consider the following cross: A/a ; B/b ; C/c ; D/d ; E/e
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(Problem 47b, part 2) Consider the following cross:A/a ; B/b ; C/c ; D/d ; E/e × a/a ; B/b ; c/c ;D/d ; e/e
Assuming independent assortment, what proportion of progeny will be genotypically the same as the second parent? 1/32 31/32 1/16 15/16 3/8 (Problem 47b, part 3) Consider the following cross:
A/a ; B/b ; C/c ; D/d ; E/e × a/a ; B/b ; c/c ; D/d ; e/e
Assuming independent assortment, what proportion of progeny will be genotypically the same as either parent? 1/32 31/32 1/16 15/16 3/8 (Problem 47b, part 4) Consider the following cross:
A/a ; B/b ; C/c ; D/d ; E/e × a/a ; B/b ; c/c ; D/d ; e/e
Assuming independent assortment, what proportion of progeny will be genotypically the same as neither parent? 1/32 31/32 1/16 15/16 3/8 (Problem 41c) You have three dice: one red (R), one green (G), and one blue (B). When all three dice are rolled at the same time, calculate the probability of the following outcome: 6 (R), 5 (G), 4 (B). 1/3 1/2 1/6 3/216 1/216 (Problem 41e) You have three dice: one red (R), one green (G), and one blue (B). When all three dice are rolled at the same time, calculate the probability of the following outcome: a different number on all dice. 5/9 5/6 2/3 1 11/18 (Problem 43b) The ability to taste the chemical phenylthiocarbamide is an autosomal dominant phenotype, and the inability to taste it is recessive. Suppose a taster woman with a nontaster father marries a taster man who in a previous marriage had a nontaster daughter.
What is the probability that their first two children will be tasters of either sex? 1/16 1/8 3/4 2/3 9/16 (Problem 45) Holstein cattle are normally black and white. A superb black-and-white bull, Charlie, was purchased by a farmer for $100,000. All the progeny sired by Charlie were normal in appearance. However, certain pairs of his progeny, when interbred, produced red-and-white progeny at a frequency of about 25 percent. Charlie was soon removed from the stud lists of the Holstein breeders. Why? Some of Charlie's F1 progeny appear to have undergone spontaneous mutations. This suggests that Charlie's gametes may be unstable. Charlie is not pure breeding, because in the F2 there were two types of progeny. Removing Charlie was a mistake. It was his F1 progeny that should have been removed. Either Charlie or his mate is not pure-breeding, because in the F2 there were two types of progeny. Removing Charlie was a mistake. It was his mate that introduced the genes that produced red-and-white cows. (Problem 47b, part 2) Consider the following cross:
A/a ; B/b ; C/c ; D/d ; E/e × a/a ; B/b ; c/c ;D/d ; e/e
Assuming independent assortment, what proportion of progeny will be genotypically the same as the second parent? 1/32 31/32 1/16 15/16 3/8
Explanation / Answer
41c. Ans- 1/216
Explanation:
For each dice, there is only one chance out of six to get the above result.
Therefore, 1/6× 1/6 × 1/6= 1/216
41e.Ans- 5/9
Explanation:
To count the number of ways and divided by the number of possible dice rolls(216). The first one has 6 ways to choose the number and the second one has 5 options, and the 3rd has 4.Therefore, 6×5×4 ways.
6×5×4/216 = 5×4/36 = 5/9.
43b.Ans- 9/16
Explanation:
The probability of a taster is ¾ and a nontaster is ¼.
The probability of taster for first two children =p ( taster for the first child) × p (taster for second child)
=3/4×3/4
=9/16
45.Ans- Either Charlie or his mate is not pure-breeding because in the F2 there were two types of progeny.
Explanation:
Charlie or his mate, or both were not pure-breeding because his F2 progeny were of two phenotypes. Let
A = black and white
a = red and white.
If both parents were heterozygous, then red and white would not have observed in the F1 generation and therefore, only one of the parents was heterozygous. The cross is:
P Aa x AA
F1 1 Aa 1 AA
When two F1 heterozygotes (Aa) crossed then
Aa x Aa
1 AA (black and white) : 2 Aa (black and white) : 1 aa (red and white).
The farmer acted correctly if he crossed the red and white F2 progeny more than one mate of Charlie’s.
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