In a loop-the-loop ride a car goes around a vertical, circular loop at a constan

Question

In a loop-the-loop ride a car goes around a vertical, circular loop at a constant speed. The car has a mass m = 252.0 kg and moves with speed v = 14.9 m/s. The loop-the-loop has a radius of R = 9.3 m.
1) What is the magnitude of the normal force on the care when it is at the bottom of the circle? (But as the car is accelerating upward.)

2) What is the magnitude of the normal force on the car when it is at the side of the circle (moving vertically upward)?
3) What is the magnitude of the normal force on the car when it is at the top of the circle?

Explanation / Answer

1) normal force = N = mg + mv^2/r = 8485.4 N 2) normal force = N' = mv^2/r = 6015.8 N 3) normal force = mv^2/r - mg = 3546.1 N

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