Use GAUSS\'S LAW: A this cylindrical shell of radius r1 is surrounded by a secon

Question

Use GAUSS'S LAW: A this cylindrical shell of radius r1 is surrounded by a second concentric cylindrical shell of radius r2. the inner shell has charge density +lambda and the outer shell has a charge density of -lambda. Find E for i) 0 to r1 , ii) r1 to r2 , iii) beyond r2.

Explanation / Answer

(i) there is no field inside the inner conductor since a Gaussian surface encloses no net charge (iii) the field is zero here also for R > r2 (ii) Let y be the charge density (charge / length) Flux = q / e0 where e0 is the electric permittivity Flux = L y / e0 for a Gaussian surface of length L E = Flux / Area = (1 / (2 pi R L) * L y / e0 E = y / (2 pi e0 R) for r1

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