(Use km and km/h as units for position and velocity) At t=0s, Ship A is 4.00km N

Question

(Use km and km/h as units for position and velocity)

At t=0s, Ship A is 4.00km NORTH and 2.50km EAST from ship B. Ship A has a velocity of 22.0km/h directed SOUTH, while ship B has a velocity of 40.0km/h NORTH-EAST with an angle of 36.9 degrees EAST.

a) What is ship A's speed in relative to ship B in vector ( )

is actual relative position at t=0s.

b) Express

in a unit vector notation.

The distance between the ships is smallest at t=t min

c) What is the value of tmin?

d) What is the value of the smallest distance?

Explanation / Answer

Xab = 2.5 i + 4 j Va = -22 j Vb = 24.01 i + 31.98 j a) Vab = - 46 i +- 31.98 j b) magnitude = 56.024 and 145.2 degrees with + x axis in anti clock wise direction

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.