1. A capacitor consists of two closely spaced metal conductors of large area, se

Question

1. A capacitor consists of two closely spaced metal conductors of large area, separated by a thin insulating foil. It has an electrical capacity of 3000.0 ?F and is charged to a potential difference of 81.0 V. Calculate the amount of energy stored in the capacitor.

2. Calculate the charge on this capacitor when the electrical energy stored in the capacitor is 7.14 J.

3. If the two plates of the capacitor have their separation increased by a factor of 5 while the charge on the plates remains constant, by what factor is the energy stored in the capacitor increased?

Explanation / Answer

1. Q = C V ( Q is charge, C is capacitance and V is volts ) E = 1/2 C V^2 = .5*3000*10^-6 81^2 = 9.841 J 2. 7.14 = .5* C 81^2 = 2176.5 µF 3.The electric field between the plates is constant. So the force is constant. as you move the plates apart you are having to add energy. The total energy = F * d. Given that the force is constant, 5 times the distance = 5 times the energy.

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