Two speakers are driven by a common oscillator at 850 Hz and face each other at

Question

Two speakers are driven by a common oscillator at 850 Hz and face each other at a distance of 1.23 m. Locate the points along a line joining the two speakers where relative minima of the amplitude of the pressure would be expected. (Use v = 343 m/s. Choose one speaker as the origin and give your answers in order of increasing distance from this speaker, for 6 consecutive distances.

Explanation / Answer

1.23/2 = 0.615m 343 = 850*(2)*x =>x = 0.201765m Then there is a node at 0.615 – ½0.201765 = 0.514117647 m a node at 0.514117647 – 0.201765 = 0.312352941 m a node at 0.312352941 – 0.201765 = 0.110588235 m a node at 0.514117647 + 0.201765 = 0.715882353 m a node at 0.715882353 + 0.201765 = 0.917647059 m & a node @ 0.917647059 + 0.201765 = 1.119411765 m from either speaker.

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