Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 10.0 m/s at an angle 36.0 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.
5) After catching the ball, Sarah throws it back to Julie. The ball leaves Sarah's hand a distance 1.5 meters above the ground, and is moving with a speed of 11.0 m/s when it reaches a maximum height of 5.0 m above the ground.
What is the speed of the ball when it leaves Sarah's hand?
6) How high above the ground will the ball be when it gets to Julie? (note, the ball may go over Julie's head.)

Explanation / Answer

T=2vsin/g=2.422s

distance d= vcos*T=17.975 m

ucos=d/1.796 = 10s

11=usin*1.796^2/2g=> usin=66.83

dividing we get tan=6.68 , =81.49

velocity =67.57 m/s

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