A blue ball is thrown upward with an initial speed of 23.3 m/s, from a height of

Question

A blue ball is thrown upward with an initial speed of 23.3 m/s, from a height of 0.7 meters above the ground. 2.9 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 12.2 m/s from a height of 30.8 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2. -How long does it take the blue ball to reach its maximum height? -What is the maximum height the blue ball reaches? -What is the height of the red ball 3.77 seconds after the blue ball is thrown? -How long after the blue ball is thrown are the two balls in the air at the same height?

A blue ball is thrown upward with an initial speed of 23.3 m/s, from a height of 0.7 meters above the ground. 2.9 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 12.2 m/s from a height of 30.8 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2. -How long does it take the blue ball to reach its maximum height? -What is the maximum height the blue ball reaches? -What is the height of the red ball 3.77 seconds after the blue ball is thrown? -How long after the blue ball is thrown are the two balls in the air at the same height?

Explanation / Answer

a) t = 23.3/9.81 = 2.38 s

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