A jogger travels a route that has two parts. The first is a displacement vector

Question

A jogger travels a route that has two parts. The first is a displacement vector A of 3.40 km due south, and the second involves a displacement vector B that points due east. (a) The resultant displacement A+ B has a magnitude of 5.56 km. What is the magnitude of B?km What is the direction of A + B relative to due south? (in degrees) (b) Suppose that A- B had a magnitude of 5.56 km. What then would be the magnitude of B and what is the direction of A - B relative to due south? magnitude of B ?km direction of A - B relative to due south ? (in degrees)

Explanation / Answer

a.) B= sqrt(5.56^2-3.4^2) = 4.399km direction from south= tan^-1(4.399/3.4) = 52.3 degree b.) magnitude of B remains same just direction gets opposite

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