GOAL Calculate the properties of an image created by a flat refractive surface.

Question

GOAL Calculate the properties of an image created by a flat refractive surface. A small fish is swimming at a depth d below the surface of a pond What is the apparent depth of the fish as viewed from directly overhead? If the fish is 12 cm long, how long is its image? STRATEGY In this example the refracting surface is flat, so R is infinite. Hence, we can use the equation for a flat refracting surface to determine the location of the image, which is the apparent location of the fish. Find the apparent depth of the fish. Substitute n1 = 1-33 for water and p = d into the flat refraction equation. What is the size of the fish's image? Use the flat refraction equation to eliminate q from the magnification equation. Again, because q is negative, the image is virtual, as indicated in the figure. The apparent depth is three-fourths the actual depth. For instance, if d = 4.0 m, then q = -3.0 m. Suppose a similar experiment is carried out with an object immersed in oil (w = 1.5) the same distance below the surface. How does the object appear compared with its image when immersed in water? The apparent depth s large. The apparent depth s unchanged. The apparent depth s smaller. Use the worked example above to help you solve this problem. A small fish is swimming at a depth d below the surface of a pond (see figure). What is the apparent depth of the fish as viewed from directly overhead? If the fish is 11 cm long, how long is its image?

Explanation / Answer

M = h'/h = 1 =>h' = h = 11cm

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