If the image is real, then it is also inverted. If the image is virtual, the len

Question

If the image is real, then it is also inverted.
If the image is virtual, the lens must be a diverging lens.
If the image is virtual, then it is also inverted.
If the image is real, then it is also upright.
If the lens is convex, the image cannot be virtual.

Explanation / Answer

1/f = 1/di + 1/do =>1/di = 1/f - 1/do =>di = (fdo)/(do-f) M = -di/do = fdo/(f-do) If M is positive.......Image is virtual and upright If M is negative.......Image is real and inverted. For a converging or convex lens, f is +ve => M can be positive or negative.....So 2nd and last options is wrong. Therefore the correct option is.............. If the image is real, then it is also inverted.

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