A particle passes through a mass spectrometer as illustrated in the figure below

Question

A particle passes through a mass spectrometer as illustrated in the figure below. The electric field between the plates of the velocity selector has a magnitude of 8215 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0929 T. In the deflection chamber the particle strikes a photographic plate 58.3 cm removed from its exit point after traveling in a semicircle.

(a) What is the mass-to-charge ratio of the particle?
kg/C

(b) What is the mass of the particle if it is doubly ionized?
kg

(c) What is its identity, assuming it's an element?

A particle passes through a mass spectrometer as illustrated in the figure below. The electric field between the plates of the velocity selector has a magnitude of 8215 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0929 T. In the deflection chamber the particle strikes a photographic plate 58.3 cm removed from its exit point after traveling in a semicircle. (a) What is the mass-to-charge ratio of the particle? kg/C (b) What is the mass of the particle if it is doubly ionized? kg (c) What is its identity, assuming it's an element?

Explanation / Answer

to find the charge to mass ratio (specific charge) of an atom you have to find both the charge of the nucleus and the mass of the nucleus charge of nucleus = proton number x charge of 1 proton (1.6x10^-19) mass of nucleus = nucleon number x mass of 1 proton (1.67x10^-27) the you have to divide the charge of the nucleus by he mass of nucleus e.g Q/M the answer should be in C/kg or Ckg^-1

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