1)Where must an object be placed in front of a converging lens to get a virtual
ID: 2153530 • Letter: 1
Question
1)Where must an object be placed in front of a converging lens to get a virtual image?at twice the focal point
between the focal point and twice the focal point
between the lens and the focal point
at the focal point
2)An object is located 5 cm from a thin diverging lens having a focal length of -10 cm. What is the magnification?
0.67
3.3
2.0
0.15
3)A 25 cm focal length mirror has a 3.0 cm tall object placed 20 cm in front of it. Where is the image, and is it real or virtual?
45 cm behind the mirror, virtual
100 cm behind the mirror, virtual
100 cm in front of the mirror, real
11 cm in front of the mirror, real
5.0 cm behind the mirror, virtual
4)A 6.0 cm tall object is placed 20 cm in front of a convex mirror with focal -100 cm focal length. Which of the following describes the image?
not possible to determine
real and upright
real and inverted
virtual and upright
virtual and inverted
5)An object is 6.0 cm from a thin lens along the axis of the lens. If the lens has a focal length of 9.0 cm, determine the image magnification.
-1.5
+3
-3
+1.5
6)A container is filled with fluid 1, and the apparent depth of the fluid is 5.00 cm. The container is next filled with fluid 2, and the apparent depth of this fluid is 4.00 cm. If the index of refraction of the first fluid is 1.60, what is the index of refraction of the second fluid?
More information is needed to find the value.
1.79
2.00
1.28
7)A convex mirror produces an erect image 1/4 the size of the object. The magnitude of the radius of curvature is 20 cm. What is the image distance?
-7.5 cm
-36 cm
+36 cm
+7.5 cm
8)Two lenses, the first with focal length 10.0 cm and the second with focal length -12.5 cm, are separated by 20.0 cm. An object, 2.40 cm tall, is 15.0 cm in front of the first lens. What is the size of the final image?
4.80 cm
12.4 cm
2.40 cm
24.0 cm
0.96 cm
9)A convex mirror with focal length of -20 cm forms an image 12 cm behind the surface. Where is the object located as measured from the surface?
30 cm
22 cm
15 cm
7.5 cm
10)A 25 cm focal length mirror has a 3.0 cm tall object placed 20 cm in front of it. What is the size of the image and is it upright or inverted?
12 cm, upright
1.0 cm, upright
2.4 cm, inverted
3.8 cm, inverted
15 cm, upright
please do not bull crap these answers... i will red flag them if they are... Will rate high and please show all work
Explanation / Answer
The focal length is half the radius of the ball (and negative for a convex mirror). Then use: 1/o + 1/i = 1/f = -2/r And solve for your image distance: i = (o-f) / of = - (r + 2o) / or The negative answer means the image is behind the mirror--virtual image. The magnification is: M = - i/o = (r+2o)/r Positive magnification means the image is upright.
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