Will rate Life saver!! thanks in advance. Suppose you drill a tunnel through the

Question

Will rate Life saver!! thanks in advance.

Suppose you drill a tunnel through the earth along a diameter and drop a stone of mass m=l.43 kg down the tunnel. The force of gravity within the volume of Earth (as described in the example 12.10 in textbook) is radially inward and equals to: where r is the radial distance from the center of earth. R, G, ME are constants with their values shown below. Assuming the density of Earth is constant and no friction or air resistance in the tunnel, the stone will travel all the way until it reaches the other end of the tunnel then travel back to your hand under the effect of the restoring gravitational force in the above equation. How long (in minutes) is the journey of the stone from the moment you drop it off to the moment when you catch it? The mass of Earth is ME = 5.972 Times 1024 kg, Radius of Earth is R= 6378 km, The gravitational constant is G = 6.67384 Times 10-11m3 / kg s2.

Explanation / Answer

GmM x/R^3 = m vdv/dx find v interms of x then use v = dx/dt and integrate again to find x in terms of t then put values of x , two major sides , and get difference in time

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.