*fig 1 cannot upload image, please draw free body diagram and solve* A block of
ID: 2150412 • Letter: #
Question
*fig 1 cannot upload image, please draw free body diagram and solve*A block of mass 1.00 m kg sits on an inclined plane as shown. A force of magnitude 20.0 N is pulling the block up the incline. The coefficient of kinetic friction between the plane and the block is 0.500. The inclined plane makes an angle 40.0 degrees with the horizontal.
a. What is the total work W_fric done on the block by the force of friction as the block moves a distance 7.00 m up the incline?
Express the work done by friction numerically, in Joules.
b. What is the total work W_F done on the block by the applied force F_vec as the block moves a distance 7.00 m up the incline?
Express your answer numerically, in Joules.
draw fig 2 for free body diagram
Now the applied force is changed so that instead of pulling the block up the incline, the force pulls the block down the incline.
c. What is the total work W_fric done on the block by the force of friction as the block moves a distance 7.00 m down the incline?
Express your answer numerically, in Joules.
d. What is the total work W_F done on the box by the applied force 20.0 N in this case?
Express your answer numerically, in Joules.
Explanation / Answer
the force acting on the mass is F = ma or a = F/m where F = 20.0 N and m = 1.00 kg the work done by frictional force is W_fric = F_fric * S where F_fric = ma * u_k * cosA where u_k = 0.500,A = 40.0 degrees the total work done W_F is W_F = ma * S * cosA
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