On a touchdown attempt, a 95.0 kg running back runs toward the end zone at 3.75

Question

On a touchdown attempt, a 95.0 kg running back runs toward the end zone at 3.75 m/s. A 111. kg linebacker moving at 4.10 m/s meets the runner in a head on collision. If the two players stick together,
a) What is their velocity immediately after the collision?
b) What are the initial and final kinetic energies of the system?
c) What caused the difference?

I have calculated the velocity immediately after the collision to be 3.94m/s using the equation below:
v=(m1v1 + m2v2)/(m1+m2).

Please show work on how to calculate the INITIAL and FINAL KINETIC energies of the system

THANK YOU

Explanation / Answer

A) v = - 0.48 m/s B) Initial KE = sum of the two individual KEs (energy is a scalar quantity .. don't account for direction) ½.95.(3.75)² + ½.111.(4.1)² .. .. ?= 1600 J

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