In order to get that pesky pig you launch a bird at an angle large enough to pas

Question

In order to get that pesky pig you launch a bird at an angle large enough to pass over the barrier. The pig is 80m from the launching point and the barrier is 30m from the launching point. The bird is in the air for a total of 3 seconds before it hits the pig. Assume that the initial height of the bird and the pig are the sa,e.
a) What is the initial horizontal speed?
answer= 27
How do you solve it?

b) What is the max height of the bird above the ground?
answer=11 how do you solve?

c) How high is the bird the ground when it passes over the barrier?
answer=12.6
how do you solve it?

Explanation / Answer

a.initial horizontal speed=horizontal distance/time=80/3=26.667 m/s ~ 27 m/s b. if the angle of projection is theta and initial speed=v then time=2*v*sin(theta)/g =3 so v*sin(theta)=3g/2 so max. height=v^2*(sin(theta))^2/(2g)=9g/8=11.025 m c. as horizontal velocity(initial)=80/3m/s time taken to reach the barrier=30/(80/3)=9/8 sec vertical component of initial velocity=v*sin(theta)=3g/2 so height at t=9/8 sec (3g/2)*(9/8) -0.5*g*(9/8)^2=12.6 m

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