The biggest asteroid (asteroid 2005 YU55 400m wide) to cruise by the earth in 35

Question

The biggest asteroid (asteroid 2005 YU55 400m wide) to cruise by the earth in 35 years, November 8, 2011 at 6:25p.m. According to NASA, at the point of closest approach, it was no closer than 324,600km from the center of the earth. Let us assume that Asteroid 2005 YU55 has a mass of 10 billion kg.
A) calculate the gravitational force of attraction between the asteroid and the earth the point of closest
approach. Assume that the asteroid goes into circular orbit at a distance of 324,600 km from the
center of the earth.
b) find the acceleration and speed of the asteroid in its circular orbit

Explanation / Answer

A) force, F = GMm/R^2 , M and m are masses of earth and asteroid, R = distance from centre. B) mv^2/R = F from this you get v, the speed and acceleration = v^2/R

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.