Three particles are located on the same line. Find resultant force on the centra

Question

Three particles are located on the same line. Find resultant force on the central particle if d = 20 cm, m1 = 2 kg and m2 = 0.5 kg and m3 = 0.5 kg (G = 6.67 Times 10-11m3 kg-1s-2) 250 Times 10-11 N to the left 250 Times 10-11 N to the right 500 Times 10-11 N to the left 500 Times 10-11 N to the right 0 N A skier of mass 63 kg skis straight down a 10 degree slope at constant velocity. The force resistance has a magnitude of 76 N. Find the frictional force on the skis. ON 31.2 N 76.0 N 107.2 N 608.0 N

Explanation / Answer

11) F21 = G.m2.m1/d2 (direction to left)

      F23 = G.m2.m3/d2 ( direction to right )

FR = F21 - F23 = G.m2/d2.[m1 - m3] = 6.67.10-11.1/0.22.[2 - 0.5] = 2.50x10-9 = 250x10-11N direction to left

12) F = 0

      mg sin - Fr - f = 0

     f = mg sin - Fr = 63.(9.8).sin 10o - 76 = 31.21 N

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