The figures below depict carts moving along a horizontal surface at the speeds s

Question

The figures below depict carts moving along a horizontal surface at the speeds specified. The masses of
the carts vary; specific values are given in the figures. The carts hit, compress the springs to some
maximum amount, and then rebound. All of the spring systems are identical, exerting the same force on
the carts, and the carts all hit the springs exactly the same way. The carts are not self-propelled, so they
compress the springs for some maximum amount of time before stopping.

Rank the situations in order from the greatest time of compression to the least time of compression. That
is, put first the cart that takes the longest time to reach maximum compression, and put last the cart that
takes the shortest time.

The answer from greatest to least is C=F=G B D=E A=H

but I am not sure why this is correct. an explanation why would be very helpful

Explanation / Answer

Higeher the momentum the lesser compression time would be:

Comparing momentum

k = m x v

A) 2 x 8= 16 J

B) 8 x 4= 32 J

C) 4 x 12= 48 J

D) 6 x 4= 24 J

E) 2 x 12= 24 J

F) 8 x 6= 48 J

G) 8 x 6= 48 J

H) 4 x 4= 16 J

Hence, Teh answer is C=F=G > B > D=E > A=H

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