Use the exact values you enter in previous answer(s) to make later calculation(s

Question

Use the exact values you enter in previous answer(s) to make later calculation(s).

A 1,275-kg car traveling initially with a speed of 25.0 m/s in an easterly direction crashes into the rear end of a 8,600-kg truck moving in the same direction at 20.0 m/s (see figure below). The velocity of the car right after the collision is 18.0 m/s to the east.

A 1,275-kg car traveling initially with a speed of 25.0 m/s in an easterly direction crashes into the rear end of a 8,600-kg truck moving in the same direction at 20.0 m/s (see figure below). The velocity of the car right after the collision is 18.0 m/s to the east.

Explanation / Answer

A)V=[2*m1*u1/(m1+m2)]+[(m2-m1)*u2/(m1+m2)].....

V=21.29 m/s(east)


B)mech.energy lost=K.Ef-K.Ei=2155585.63-[2192733.76]=-37148.13 J

during collision some energy goes as the heat energy

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