The conducting rod shown in the figure below has a length L and is being pulled

Question

The conducting rod shown in the figure below has a length L and is being pulled along horizontal, frictionless, conducting rails at a constant velocity . The rails are connected at one end with a metal strip. A uniform magnetic field , directed out of the page, fills the region in which the rod moves. Assume that L = 19 cm, = 3.6 m/s, and = 1.1 T. What is the magnitude and direction of the emf induced in the rod? (Take up to be positive.) What is the magnitude and direction of the current in the conducting loop? (Take counterclockwise to be positive.) Assume that the resistance of the rod is 0.40 and that the resistance of the rails and metal strip is negligibly small. At what rate is thermal energy being generated in the rod? What external force on the rod is needed to maintain ? At what rate does this force do work on the rod?

Explanation / Answer

1) induced emf = B*V*L = 1.1*3.6*0.19 = 0.7524 volts

upper end is at positive potentail and lower end at negative potential.


2) i = emf/R = 1.881 A

3) p = i*emf = 1.415 watts

4) P = F*v

F = P/v = 1.415/3.6 = 0.393 N

5) P = F*v = 1.415 watts

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