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Question Part Points Submissions Used A place-kicker must kick a football from a

ID: 2143765 • Letter: Q

Question


Question Part Points Submissions Used A place-kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. Half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 22.0 m/s at an angle of 52.0° to the horizontal. By how much does the ball clear or fall short (vertically) of clearing the crossbar? (Enter a negative answer if it falls short.)


Please show work
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used A place-kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. Half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 22.0 m/s at an angle of 52.0° to the horizontal. By how much does the ball clear or fall short (vertically) of clearing the crossbar? (Enter a negative answer if it falls short.)


Please show work A place-kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. Half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 22.0 m/s at an angle of 52.0° to the horizontal. By how much does the ball clear or fall short (vertically) of clearing the crossbar? (Enter a negative answer if it falls short.)


Please show work Question Part Points Submissions Used A place-kicker must kick a football from a point 36.0 m (about 40 yards) from the goal. Half the crowd hopes the ball will clear the crossbar, which is 3.05 m high. When kicked, the ball leaves the ground with a speed of 22.0 m/s at an angle of 52.0Â degree to the horizontal. By how much does the ball clear or fall short (vertically) of clearing the crossbar? (Enter a negative answer if it falls short.)

Explanation / Answer

The time to travel 36 m is given by
t = 36 / 20 cos 52 = 2.923 s.

In this time it travels a vertical height given by
h = 20 sin 53*2.991

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