Please help. Two conductors having net charges of + 15.0 mu C and - 15.0 mu C ha
ID: 2142974 • Letter: P
Question
Please help.
Explanation / Answer
a) Q = CV
so C = Q/V = 15.0E-6/15 = 1.0E-6 F
b) V = Q/C = 225.0E-6/1.0E-6 = 225 V
2)
a)C = 2 pi e0 L/ln(b/a)
= 2*pi*8.85E-12*73/(ln(7.27/2.58)=3.92 nF
b) V = Q/C = 8.1E-6/3.92E-9=2066 V = 2.066 kV
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