A 56 k g skier encounters a dip in the snow\'s surface that has a circular cross

Question

A 56kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12 m.If the skier's speed at point A in the figure is 8.5 m/s, what is the normal force exerted by the snow on the skier at point B? Ignore frictional forces. Express answer using two significant figures.

A 56kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12 m.If the skier's speed at point A in the figure is 8.5 m/s, what is the normal force exerted by the snow on the skier at point B? Ignore frictional forces. Express answer using two significant figures.

Explanation / Answer

h = 1.75 m
v1 = 8.5 m/s

m*g*h + 0.5*m*v1^2 = 0.5*m*v2^2

v2 = sqrt(v1^2 + 2*g*h) = 10.32 m/s

N = m*g + m*v2^2/R
= 56*9.8 + 56*10.32^2/12
= 1045.8 N

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