A block with mass m = 0.50 kg is forced against a horizontal spring of negligibl

Question

A block with mass m = 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m. When released, the block moves on a horizontal table top for 1.00 m before coming to rest. The spring constant k is 120 N/m. What is the coefficient of kinetic friction, µk between the block and the table?

A block with mass m = 0.50 kg is forced against a horizontal spring of negligible mass, compressing the spring a distance of 0.20 m. When released, the block moves on a horizontal table top for 1.00 m before coming to rest. The spring constant k is 120 N/m. What is the coefficient of kinetic friction, A mu k between the block and the table?

Explanation / Answer

First you calculate teh force of the block by using hooke's law. F=-k(x1-x0). You find that the force is 24N. You then set that equal to distance times kinetic friction. Kinetic friction equals ( Normal force of the object * the coefficient of friction). 24N = distance he block travels (1m) * Normal force of the block (9.81m/s^2 * .5 kg)* coefficient. You find that the answer is 4.89N

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