The two wires shown in the figure below are separated by d = 12.1 cm and carry c

Question

The two wires shown in the figure below are separated by d = 12.1 cm and carry currents of I = 4.95 A in opposite directions.

magnitude The two wires shown in the figure below are separated by d = 12.1 cm and carry currents of I = 4.95 A in opposite directions. Find the magnitude and direction of the net magnetic field at a point midway between the wires. Find the magnitude and direction of the net magnetic field at point P1, 12.1 cm to the right of the wire on the right. Find the magnitude and direction of the net magnetic field at point P2, 2d = 24.2 cm to the left of the wire on the left.

Explanation / Answer

magnetic field due to i1 at d/2 is B1=u0i1/2pid/2

magnetic field due to i2 at d/2 is B2=u0i1/2pid/2

since currrentare travelling in opposite directions, Bnet=B1+B2

thus Bnet=u0/pid)(i1+i2)

Bnet =4*10^-7*4.95*2/0.121

Bnet=3.27*10^-5 T

similarly you solve for

b. Bnet = u0i1/pi)(1/d +1/2d)

and

c. Bnet =uoI/pi(1/2d+1/3d)

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