1. what is Tx? N right. 2. what is Ty? N up. 3. what is the Normal Force? N up.

Question

1. what is Tx?       N right.

2. what is Ty?       N up.

3. what is the Normal Force?            N up.

4. what is the Friction?                   N right.

5. What is the net force on the block in the x-direction?        N right.

6. What is the net force of the block in the y-direction?        N up.

7. What is the acceleration of the block?            m/sec^2 right.

8.  What will be the position of the block after 7 seconds if it starts from a position 3 m from the left of the origin at a speed of 5 m/sec right?         m right.

9. What will be the velocity of the block at this time?       m/sec right.

a mass is 4.20 kg, T = 23 N, and theta 31 degrees. The surface does have friction, with s = .45 and k = .39. If x is horizontal and y is vertical...

Explanation / Answer

1) Tx (right) = Tcos31 = 23 * cos(31 degrees) = 19.71 N

2) Ty (up) = Tsin31 = 23 * sin(31 degrees) = 11.84 N

3) Normal Force = mg - Ty(up) = (4.2 * 9.8) - 11.84 = 29.32 N

4) Frictional Force maximum = usN = 0.45 * 29.32 = 13.194 N, and the horizontal force is greater than this so the body will start moving

Hence the frictional force acting is ukN = 0.39 * 29.32 = 11.43 N

5) Net force = 19.71 - 11.43 = 8.28 N

6) Net force in the y direction is 0.

7) Acceleration = 8.28/4.2 = 1.97 m/s^2

8) s = ut + 0.5at^2 = (5 * 7) + (0.5*1.97*49) = 83.26 m

Hence its position is 80.26 m to the right of origin (83.26 - 3) m

9) speed = u + at

5 + (1.97*7) = 18.79 m/s

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