Linear polarized light is sent through two polarizers, the first at 45 deg to th

Question

Linear polarized light is sent through two polarizers, the first at 45 deg to the original polarization direction and the second at 90 deg to the original polarization direction. What fraction of the original polarized intensity passes through the last polarizer? A. 0      B. 1/2      C. 1/4      D. 1/8      E. 1/10 Linear polarized light is sent through two polarizers, the first at 45 deg to the original polarization direction and the second at 90 deg to the original polarization direction. What fraction of the original polarized intensity passes through the last polarizer? A. 0      B. 1/2      C. 1/4      D. 1/8      E. 1/10 Linear polarized light is sent through two polarizers, the first at 45 deg to the original polarization direction and the second at 90 deg to the original polarization direction. What fraction of the original polarized intensity passes through the last polarizer? A. 0      B. 1/2      C. 1/4      D. 1/8      E. 1/10 Linear polarized light is sent through two polarizers, the first at 45 deg to the original polarization direction and the second at 90 deg to the original polarization direction. What fraction of the original polarized intensity passes through the last polarizer? A. 0      B. 1/2      C. 1/4      D. 1/8      E. 1/10 A. 0      A. 0      B. 1/2      B. 1/2      C. 1/4      C. 1/4      D. 1/8      D. 1/8      E. 1/10

Explanation / Answer

I=I0*cos^theta
I=10*cos^245
=5

and then theta=90
I=5*cos^290
=0 ans
A is correct

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