Two electromagnets, A and B, have a different number of turns and a different cu

Question

Two electromagnets, A and B, have a different number of turns and a different current in them. Electromagnet A has more turns than B (in the same amount of space), and electromagnet A has more current through it than B. How does the strength of their magnetic fields compare?

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Two electromagnets, A and B, have a different number of turns and a different current in them. Electromagnet A has more turns than B (in the same amount of space), and electromagnet A has more current through it than B. How does the strength of their magnetic fields compare?

a. the magnetic field strength of A is less than that of B b. we need to know the current to determine an answer c. we need to know the number of turns to determine an answer d. the magnetic field strength of A is equal to that of B e. the magnetic field strength of A is greater than that of B

Explanation / Answer

strength

B= u*N*I

here

N= no of turns

i= current

as

Na >Nb

iA> ib

so

u is a const so we can omit while comparing

Ba = NA IA

B b = NA iB

but

Na >Nb

iA> ib

so

NA *Ia > Nb *Ib

wgich means

B a> Bb

so

e.the magnetic field strength of A is greater than that of B

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