An 835 -kg race car can drive around an unbanked turn at a maximum speed of 52 m

Question

An 835-kg race car can drive around an unbanked turn at a maximum speed of 52 m/s without slipping. The turn has a radius of curvature of 175 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 10900 N on the car.

An 835-kg race car can drive around an unbanked turn at a maximum speed of 52 m/s without slipping. The turn has a radius of curvature of 175 m. Air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 10900 N on the car. What is the coefficient of static friction between the track and the car's tires? What would be the maximum speed if no downforce acted on the car?

Explanation / Answer

a)

u = mv^2/(r*(mg+F)) = 835*52^2/(175*(835*9.8+10900)) = 0.68

b)

max speed = sqrt(urg) = sqrt(0.68*175*9.8) = 34.15 m/s

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