Kinetic & Static Frictions of the Block Block With No Added Weights 170.5g Added
ID: 2140391 • Letter: K
Question
Kinetic & Static Frictions of the Block
Block With No Added Weights 170.5g
Added Weight (g)
Sand Added (g)- Kinetic Friction
Sand Added (g)- Static Friction
0
37.5
58.5
100
70.0
76.0
200
80.5
115
300
104.0
134.5
500
171
204.5
Error Analysis: Kinetic & Static Frictions of the Block
Block With 300g Added
Trial
Sand Added (g) -Kinetic Friction
Sand Added (g) -Static Friction
1
104.5
143.0
2
110.0
140.5
3
114.0
137.5
4
106.5
134.5
5
104.0
134.0
Average (g)
107.8
137.9
Percent Uncertainty
105.8%
103.7%
First off, this is a sliding block experiment that is on a flat surface. The block is on a flat surface on a table and is connected to a pulley. The pulley is connected to a container where you add sand and is hanging off the edge of the table.
1. I need help finding the force (not mass) applied by the sand and the force exerted on the track by the block and its load for the kinetic and static (normal force).
2. I also need help finding the coeffecients of friction for the block in all cases.
3. Finally, Determine the absolute uncertainty for each by using the equation: ?? = ?*(?m_max/m_avg)
Any help would be greatly appreciated! Thanks!
Kinetic & Static Frictions of the Block
Block With No Added Weights 170.5g
Added Weight (g)
Sand Added (g)- Kinetic Friction
Sand Added (g)- Static Friction
0
37.5
58.5
100
70.0
76.0
200
80.5
115
300
104.0
134.5
500
171
204.5
Explanation / Answer
If I understand this you add sand until the block slides and also
find the sand required for the block to slide at constant speed
m g = u M g where m is mass of sand and container
u = m / M
1) u = 58.5 / 170.5 = .34
2) u = 76 / 270.5 = .28
3) u = 115 / 370.5 = .31
4) u = 134.5 / 470.5 = .29
5) u = 204.5 / 670.5 = .30
The coefficients for kinetic friction are calculated in the same way
The formula that I would use for the uncertainty is
Del u = del m / M assuming that there is no uncertainty in M
the mass of the block ad the added weight.
Applying this to your last table
Pct u = +- 6 / 470.5 = 1.3 % using about 6g for uncertainty sand added
u = 137.9 / 470.5 = .29 with a percent error of +- 1.3 %
Then do the same for the kinetic friction
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