Problem 26.45 Two 3.4 ? F capacitors, two 2.1 k ? resistors, and a 12.2 V source
ID: 2140324 • Letter: P
Question
Problem 26.45 Two 3.4?F capacitors, two 2.1k? resistors, and a 12.2Vsource are connected in series. Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = s Problem 26.45 Two 3.4?F capacitors, two 2.1k? resistors, and a 12.2Vsource are connected in series. Problem 26.45 Two 3.4?F capacitors, two 2.1k? resistors, and a 12.2Vsource are connected in series. Two 3.4?F capacitors, two 2.1k? resistors, and a 12.2Vsource are connected in series. Two 3.4?F capacitors, two 2.1k? resistors, and a 12.2Vsource are connected in series. Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = s Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = s Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = s Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = s Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = s Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = s t = s t = s Problem 26.45 Two 3.4?F capacitors, two 2.1k? resistors, and a 12.2Vsource are connected in series. Part A Starting from the uncharged state, how long does it take for the current to drop from its initial value to 1.80mA ? Express your answer using two significant figures. t = sExplanation / Answer
when the 3.4?F capacitors are in series , equivalent capacitence is : 3.4?F x 3.4?F / 3.4?F+ 3.4?F = 1.7 ?F equivalent resistence : = 2.1k? + 2.1k = 4.2k? Current = I = 1.8 mASo, which means the voltage across the 4.2k? is = (4.2)(1.8) = 7.56 volts that leaves 4.64 volts across the C Thus, time constant of the circuit is : RC = (4.2k?) (1.7?F ) = 7.14 ms Hence , for RC circuit voltage equation : v = v0[1
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