A 1.10 k g , horizontal, uniform tray is attached to a vertical ideal spring of
ID: 2139843 • Letter: A
Question
A 1.10kg , horizontal, uniform tray is attached to a vertical ideal spring of force constant 180N/m and a 285g metal ball is in the tray. The spring is below the tray, so it can oscillate up-and-down. The tray is then pushed down 13.1cm below its equilibrium point (call this point A) and released from rest.
a How high above point
A will the tray be when the metal ball leaves the tray? (Hint: This does not occur when the ball and tray reach their maximum speeds.)
b How much time elapses between releasing the system at point
A and the ball leaving the tray?
c How fast is the ball moving just as it leaves the tray?
Explanation / Answer
A)13.1 cm from the equilibrium point....
B)T/2=pi*sqrt(m/k)=0.275 sec......
C)(1/2)m*v^2=(1/2)*k*x^2.......
v=sqrt(k*x^2/m)...
V=3.29 m/sec
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.