In the figure C1=C5=9 microF and C2=C3=C4=4.7 microF. The applied potential is V

Question

In the figure C1=C5=9 microF and C2=C3=C4=4.7 microF. The applied potential is Vab=210V.

A. What is the equivalent capacitance of the network between a and b, C?

B. Calculate the charge on each capacitor and the potential difference across each capacitor, Q1.

C. V1, V2,V3,V4,V5

D. Q1,Q2,Q3,Q4,Q5

In the figure C1=C5=9 microF and C2=C3=C4=4.7 microF. The applied potential is Vab=210V. What is the equivalent capacitance of the network between a and b, C? Calculate the charge on each capacitor and the potential difference across each capacitor, Q1. V1, V2,V3,V4,V5 Q1,Q2,Q3,Q4,Q5

Explanation / Answer

A) C234 = 2.35 + 4.7 = 7.05 micro F


1/Cnet = 1/c1 + 1/c234 + 1/c5

Cnet = 2.75 micro F


B) Qnet = Cnet*V = 2.75*10^-6 * 210 = 576.8 micro C

Q1 = Q5 = 576.8 micro C


V1 = Q1/C1 = 64.09 volts


V2 = 210 - 2*64.09 = 81.82 volts

V3 = 81.82/2 = 40.9 volts

V4 = 81.82/2 = 40.9 volts

V5 = Q5/C5 = 64.09 volts


Q1 = Q5 = 576.8 micro C

Q2 = C2*V2 = 384.55 micro C

Q3 = Q4 = c3*v3 = 192.23 micro C

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