In the diagram shown below, the lower block is acted on by a force, F, which has

Question

In the diagram shown below, the lower block is acted on by a force, F, which has a magnitude of 109.3N. The coefficient of kinetic friction between the lower block and the surface is 0.380. The coefficient of kinetic friction between the lower block and the upper block is also 0.380. What is the acceleration of the lower block, if the mass of the lower block is 4.20kg and the mass of the upper block is 1.97kg?

In the diagram shown below, the lower block is acted on by a force, F, which has a magnitude of 109.3N. The coefficient of kinetic friction between the lower block and the surface is 0.380. The coefficient of kinetic friction between the lower block and the upper block is also 0.380. What is the acceleration of the lower block, if the mass of the lower block is 4.20kg and the mass of the upper block is 1.97kg?

Explanation / Answer

T = um1g

F - um1g - u(m1+m2)g-T = m2a

so 109.3 - 7.34 - 23 - 7.34 = 4.2a

so a = 17 m/s^2

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