In Griffith\'s EM text, he devouts 2 pages to deriving the equation for bound cu
ID: 2138077 • Letter: I
Question
In Griffith's EM text, he devouts 2 pages to deriving the equation for bound currents, and for the next 4 problems, he (the solution manual) doesn't even use the equations just introduced. I question the wisdom of deriving an equation that is harder to work with than we already had.
A? (r? )=?04?(?VJ? br?dV?+?SK? br?da?)
When using this, I always get a really really ugly integral that would be too messy to work with. I guess it has some worth from a theoretical stand point, but I don't really understand why the questions that proceed this don't use the material from the same
Explanation / Answer
Those problems are for extremely simple systems wherein the magnetic field can be easily deduced once ?
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