I found the answer to part A but cant figure out B or C. Help! A small mailbag i

Question

I found the answer to part A but cant figure out B or C. Help!

A small mailbag is released from a helicopter that is descending steadily at 1.21 m/s.

    (a) After 3.00 s, what is the speed of the mailbag?
    v =               m/s
    
    (b) How far is it below the helicopter?

(c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.21 m/s?     

A small mailbag is released from a helicopter that is descending steadily at 1.21 m/s. After 3.00 s, what is the speed of the mailbag? How far is it below the helicopter? What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.21 m/s?

Explanation / Answer

v = u + at

= 1.21 + 9.8 * 3

= 30.61 m/s

b) v^2 - u^2 = 2as

30.61^2 - 1.21^2 = 2 * 9.8 * s

s = 47.73 metres

c)

v = u + at

= -1.21 + 9.8 * 3

= 28.19 m/s

v^2 - u^2 = 2as

30.61^2 - (-1.21)^2 = 2 * 9.8 * s

s = 47.73 metres

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