I am getting stuck on part B. The answer I keep on getting is wrong and I got 1.

Question

I am getting stuck on part B. The answer I keep on getting is wrong and I got 1.951x10^-5...Please show me how to get the right answer. Thanks

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.270 T. If the kinetic energy of the electron is 3.90 Times 10-19 J, find the speed of the electron and the radius of the circular path. The speed of the electron m/s the radius of the circular path your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. mu m

Explanation / Answer

force = q(r xB) = mv^2 / r

1.6 x 10-19 x R x 0.270 = 9.109 x 10-31 x (9.25 x 10^5)^2   / R

R = 4.25 m

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