two poin charges q1 = +2.7 nc and q2=-6.25 nc are 0.100 m apart. Point A is midw

Question

two poin charges q1 = +2.7 nc and q2=-6.25 nc are 0.100 m apart. Point A is midway between them; point B is 8X10^-2 m from q1 and 6.00 X10^-2 from q2. Take the electric potential to be zero at infinity

Part A

FInd the Potential at point A

Part B

Find the potential at point B

Part C

Find the work done by the electric field on a charge of 2.8 nc that travels from point B to point A

two poin charges q1 = +2.7 nc and q2=-6.25 nc are 0.100 m apart. Point A is midway between them; point B is 8X10^-2 m from q1 and 6.00 X10^-2 from q2. Take the electric potential to be zero at infinity

Explanation / Answer

A)at point A, Vnet = v1+v2 = k*q1/0.05 + k*q2/0.05 = -639 volts

B)at point B, Vnet = v1+v2 = k*q1/0.08 + k*q2/0.06 = -633.75 volts

c)workdone = (v2-v1)*q = (-633.75-(639))*2.8*10^-9 = 14.7*10^-9 J

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