the question is showed below in picture For the most detailed mapping of the sky

Question

the question is showed below in picture

For the most detailed mapping of the sky, radio astronomers use radio telescopes placed on different continents, with (straight-line) separation of several thousands kilometers. Suppose that two such radio telescopes are separated by an east-west distance of 6.000 times 103 km, and that they are connected to a single radio receiver tuned to a wavelength of 2.0 times 101 cm. If a source is symmetrically located above these radio telescopes, the radio waves reaching the receiver will be in phase, and the receiver will register maximum intensity. What westward angular displacement of the source from this location will, again, result in maximum intensity? theta =

Explanation / Answer

d sin(theta) = m lamda

sin(theta) = theta

m =1

==> theta = lamda/d = 0.20/6e6 = 3.33 x 10^-8 radians

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