An artist wearing spiked shoes pushes two crates across her frictionless horizon

Question

An artist wearing spiked shoes pushes two crates across her frictionless horizontal studio floor. (See the figure below.)(Figure 1) Part A If she exerts a horizontal 46.0N force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to If she exerts a horizontal 46.0 force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to 46.0N . 38.3N . 200 N. 240 N. If she exerts a horizontal 46.0 force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to 46.0N . 38.3N . 200 N. 240 N. If she exerts a horizontal 46.0 force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to 46.0N . 38.3N . 200 N. 240 N. My Answer sGive U
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p An artist wearing spiked shoes pushes two crates across her frictionless horizontal studio floor. (See the figure below.)(Figure 1) Part A If she exerts a horizontal 46.0N force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to If she exerts a horizontal 46.0 force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to 46.0N . 38.3N . 200 N. 240 N. Submit My Answer sGive U
p An artist wearing spiked shoes pushes two crates across her frictionless horizontal studio floor. (See the figure below.) (Figure 1) Part A If she exerts a horizontal 46.0N force on the smaller crate, then the smaller crate exerts a force on the larger crate that is closest to

Explanation / Answer

Consider the combined acceleration is a.

Let force appled by smaller crate on larger crate is f.
Hence force appled by larger crate on smaller crate is f.

Force by the lady =F.

Consider smaller crate.

F-f=4a

For larger crate f=20a

Adding F=24a

a=F/24=1.917m/s^2

Force on larger crate by smaller crate = f=20a=38.3N

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