One component of a magnetic field has a magnitude of 0.0379 T and points along t

Question

One component of a magnetic field has a magnitude of 0.0379 T and points along the +x axis, while the other component has a magnitude of 0.0685 T and points along the -y axis. A particle carrying a charge of +1.88

One component of a magnetic field has a magnitude of 0.0379 T and points along the +x axis, while the other component has a magnitude of 0.0685 T and points along the -y axis. A particle carrying a charge of +1.88 times 10-5 C is moving along the +z axis at a speed of 4.50 times 103 m/s. Find the magnitude of the net magnetic force that acts on the particle. Determine the angle that the net force makes with respect to the +x axis.

Explanation / Answer

a)

Fx =-qVz*By =-(1.88*10^-5)(4.5*10^3)(-0.0685)

Fx=5.795*10^-3 N

Fy=qVz*Bx =(1.88*10^-5)(4.5*10^3)(0.0379)

Fy=3.206*10^-3 N

Fnet=sqrt[Fx^2+Fy^2]=sqrt[(5.795*10^-3)^2+(3.206*10^-3)^2]

Fnet=6.62*10^-3 N or 0.00662 N

b)

theta =tan^1-(Fy/Fx) =tan^-1(3.206*10^-3/5.795*10^-3)

theta =28.95 degrees

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